# A+ Cert

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I need help on how to understand the decimal value of the binary number. Can someone possibly help me?

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Binary is a lanquage of yes or no, 1 = yes 0 no, 1 bit 1 value, and there are 8 octets possible in one bit. Which when you have 8 1's and 0's it looks like this

11111111 = 256

128X1 + 64X1 + 32X1 + 16X1 + 8X1 + 4X1 + 2X1 + 1 X1

1 1 1 1 1 1 1 1

Those place values apply to create your value

Here is the numer 128 and how it would look

128X0 + 64X1 + 32X1 + 16X1 + 8X1 + 4X1 + 2X1 + 1 X1

0 1 1 1 1 1 1 1

Because the first octet is 0 that 128 doesn't exist the overall value is 128.

If you want to get into hext hex is just a 16 based code used to simplify binary, like in Ipv6, or a mac adress

0 = 0

1 = 1

2 = 2

3 = 3

4 = 4

5 = 5

6 = 6

7 = 7

8 = 8

9 = 9

10 = A

11 = B

12 = C

13 = D

14 = E

15 = F

Even though it goes to 15, the 0 counts so its 16. That is as far as the simplification needs to go to keep 256 digits at 2 digits. i might edit this post to make it more understandable later.

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you have to know bionary for A+ ahh.. i dont or would not think so.. if so i am screwed.. because i cant remember tat.. to hard

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Binary is really easy once you pick up on it, not to make ya'll feel bad, but some of the worst students in my C++ class picked up on binary