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# Overclocking 3.2 Prescott & 533 Memory, Overclocki

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I am Confused.

I have this set up (see my sig) and I have recently installed the Zalman 7000cu with brilliant results. I have overclocked to 3.7 with no voltage rise and a temp 45.0 idle (so there is plenty left )

But I don't get this:

I have my CPU FSB set to 230, which has set my cpu to running at 3.7Ghz and my memory at 2 x 230 = 460.

I have also set my ratio to 3:2, now this is where i am stuck, no matter what i do to the ratio, the CPU speed changes directly with the FSB speed.

So to get my Memory running at the true 533 Mhz I would have to set my FSb to 266 which would in turn set my CPU to something like 4.2 ghz which currently I don't want.

So how do I set my memory at 533 without running at 4.2 Ghz?

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I have also set my ratio to 3:2, now this is where i am stuck, no matter what i do to the ratio, the CPU speed changes directly with the FSB speed.

yep, that's how it works... the cpu changes at a fixed ratio... the memory however, doesn't... to have an fsb of 230 and a memory speed of 266 (533DDR) you have to make that 3:2 ratio something else...

specifically... compare 230 to 266

230 / 266 = 0.865

so you want to get nearest to that... 5:6 -> 5/6 = 0.833, that's as close as you're gonna get unless you have more dividers...

so if you have the memory divider as 5:6 (fsb:memory, might be the other way round if your bios has it down as memory:fsb) then it'll work out as:

fsb : 230

mem: 230 x 6/5 = 276 --> 552MHz DDR

so you'll be oc-ing your memory by just over 1%, in my experience even value ram oc's up to 8% so those setting should be fine...

||| the short answer |||

anyway, set the divider at 5:6 (or 6:5, whichever makes the memory faster) and set the fsb at 222MHz which will give you the memory at 533MHz!

whew! give that a try and let me know how it works out...

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nevermind post above didn't show right on my comp before I posted

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Wicked, thanks for taking the time to reply I get it, and yes it worked.

I always thought that the CPU speed changed, but by changing the ration you are actually changing the multiplier for the memory, so simple, i just couldn't understand it.

Thanks for that

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