# tight timings? loose timings? dividers? 1T or 2T? 754 or 939? (read he

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275x10=2750MHZ (cpu speed)

2750 (cpu speed) '/, 11 (180 divider) = 250MHZ "DDR500"

the 200 divider or 1:1 is always the CPU multiplyer (eg. 10 in the above case)

Each step down is an increase in "1" of this number. So the 180 divider is 10+1=11..And so on..... Get it?

Sorry,

Could you please clarify the '/, thing?

Do you mean.... 2750 (cpu speed) / 11 (180 divider) = 250 MHz

If yes, then assuming the next divider, which would be /12

2750 (cpu speed) / 12 (divider after 180... 166 ?) = 299.1667 MHz. Is this right?

Have i got it now

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Sorry '/. does equal /......(divided by)..

You do have it now except that next 166 divider is 12 not 11..

In the case we are looking at, here is how the dividers look....

200=10 <-(cpu multiplier)--275mhz

180=11--250mhz

166=12--229mhz

150=13--211mhz

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2750 (cpu speed) / 11 (divider after 180... 166 ?) = 299.1667 MHz. Is this right?

I really dont know how you got these numbers, but I think you got it figured out now. Just be careful with the calculations...

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Hi 27floyd,

Previous post edited.

So, i presume the bios takes care of the ' .1667 ' MHz on DDR180 @ 275 X 10? Hence we just say the the RAM is running at 299 MHz in this scenario.

Thank you for the help

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Angry_Games 1 - Technology 0

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http://www.barrys-rigs-n-reviews.com/revie...em/pnymem_1.pdf

This is an interesting review (old by todays standards) of some PNY DDR 600 memory. What caught my eye about this review is the comparison between an Athlon64 at 2600 MHz with memory timings of 2-2-2-5 (low latency typical high priced overclockers ram) and 2.5-4-4-7 (average latency). Most of the benchmarks show a "gain" of

Enjoy,